ENGINEERING TACTICS

In this article you will get "How to calculate bricks in 1 brass"                       BRICKS IN 1 BRASS 1 brass = 2.83 cubic meter How it's come?       1m³ = 1 m x 1 m x 1 m                = 3.28084 x 3.28084 x 3.28084                = 35.315 cft               (1 meter = 3.28084 feet) As we know,       1 brass = 10 ft x 10 ft x 1 ft = 100 cft Therefore,       1 brass = 100/35.315                     = 2.83 cubic meter ( proved) We take standard size of brick;            10 cm x 10 cm x 20 cm Now convert "cm" in to "m",  we get,             0.1 m x 0.1 m x 0.2 m = 0.002 cubic meter Now calculate no.of bricks in 1 brass,        no.of bricks = 2.83 / 0.002                               = 1415 numbers. If you want to see that numerical in video,go to my following video. https://youtu.be/sIKWhAf6xKo

How to calculate quantity of Cement and Sand in Plaster? Ex:    Area of plaster = 100 ft × 100 ft    Thickness of plaster = 12mm Step 1) find out volume of plaster:  (Need to all units that is "ft" and "mm" convert into "m" )                   1000mm = 1m So that;        12mm = 0.012m                      3.28ft = 1m So that;        100ft = 30.49m     Volume of plaster = 30.49 × 30.49 × 0.012                                      = 11.15 m³ Step 2) Convert plaster volume wet to dry:              Take 33%     Dry vol = 11.15 × 1.33                   = 14.83 m³ Step 3) Consider wastage:               Take 5%      Total dry vol = 14.83 × 1.05                             = 15.57 m³ Step 4) find out Cement and sand required:               Take;                    Cement : sand                               1 : 6     Cement req = 1/(1+6) × 15.57                           = 2.22 m³             Need to cement in bags  

Derivation of steel weight calculation D²/162 Derivation :     W = c/s area × density of steel × length of steel         = (π/4 × D²) × 7850 ×1         = (3.14 × D²/4) × 7850         = 6162.25 D²         =D²/ 1.6227 × 10-⁴ [ 1m = 1000 mm ]           = D²/ 1.6227 × 10-⁴ × 1000²         = D²/ 162.27     W = D² / 162 https://youtu.be/v3_qNReDvRs

How to calculate target strength of concrete?             TARGET STRENGTH OF CONCRETE Formula;      f'ck = fck + 1.65s  Where;        S = standard deviation Grade of concrete             assumed 'S' N/mm²    M10 to M15                                     3.5    M20 to M25                                     4.0    M30 to M55                                     5.0 From  IS 10262:2009 Ex:      Concrete grade = M25 - fck                           fck = 25 N/mm² at 28 days     That's why,  fck = 17 N/mm² at 7 days    (M25 gain strength 17 N/mm² at 7 days) Solution: 1   Target strength of concrete at 7 days f'ck = fck + 1.65s         = 17 + (1.65×4)         = 23.6 N/mm² Solution: 2    Target strength of concrete at 28 days f'ck = fck + 1.65s         = 25 + (1.65×4)         = 31.6 N/mm² For Proper understanding watch this video https://youtu.be/NyFxv0jU-Ac

There are some Densities of building construction materials are as follows;       DENSITY OF BUILDING CONSTRUCTION                                       MATERIALS ● Cement - 1440 kg/m³ ● Steel - 7850 kg/m³ ● Plain cement concrete - 2400 kg/m³ ● Reinforced cement concrete - 2500 kg/m³ ● Sand - 1600 to 1850 kg/m³ ● Coarse aggregate - 1600 to 1890 kg/m³ ● Cement mortar - 2162 kg/m³ ● Water - 1000 kg/m³ ● Common red brick - 1600 to 1920 kg/m³ ● Concrete block ;    1) Dense concrete block - 1800 to 2100 kg/m³     2) Medium dense block - 650 to 1500 kg/m³    3) Aircrete block - 400 to 900 kg/m³ https://youtu.be/5mp2HTCrdLc

There are some important things site Engineers must know about reinforcement and Steel Bars are as follows;         THINGS SITE ENGINEERS MUST KNOW            ABOUT REINFORCEMENT AND STEEL BARS ● Hooks for stirrups is 9D for one side. ● No.of stirrups = (clear span/spacing ) + 1 ● For cantilever Anchorage length for main steel is 69D. ● 'L' for column main bar in footing is minimum length 300mm. ● For chairs in footing minimum 12mm dia with 1m spacing should be used. ● Lapping of steel bar should not be used for larger than 36mm. ● In steel Reinforcement binding wire required 8kg per MT. ● Weight of rod per meter = D^2/162, (D=dia of bar). ● Main bar in the slab shall not be less than 8mm (HYSD) or 10mm (plain bar). ● Distribution bar in the slab shall not be less than 8mm and not more than 1/8 of the slab thicknes. ● All reinforcement shall be free from loose rust, oil or any other substances.